1/(x2+3x)-3/(x2+2x-3)=1/(x2-x)

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Solution for 1/(x2+3x)-3/(x2+2x-3)=1/(x2-x) equation:


D( x )

x^2-x = 0

x^2+3*x = 0

x^2+2*x-3 = 0

x^2-x = 0

x^2-x = 0

x^2-x = 0

DELTA = (-1)^2-(0*1*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)+1)/(1*2) or x = (1-1^(1/2))/(1*2)

x = 1 or x = 0

x^2+3*x = 0

x^2+3*x = 0

x^2+3*x = 0

DELTA = 3^2-(0*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-3)/(1*2) or x = (-9^(1/2)-3)/(1*2)

x = 0 or x = -3

x^2+2*x-3 = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

DELTA = 2^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)

x = 1 or x = -3

x in (-oo:-3) U (-3:0) U (0:1) U (1:+oo)

1/(x^2+3*x)-(3/(x^2+2*x-3)) = 1/(x^2-x) // - 1/(x^2-x)

1/(x^2+3*x)-(3/(x^2+2*x-3))-(1/(x^2-x)) = 0

1/(x^2+3*x)-3*(x^2+2*x-3)^-1-(x^2-x)^-1 = 0

1/(x^2+3*x)-3/(x^2+2*x-3)-1/(x^2-x) = 0

x^2+3*x = 0

x^2+3*x = 0

x*(x+3) = 0

x+3 = 0 // - 3

x = -3

x*(x+3) = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

DELTA = 2^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)

x = 1 or x = -3

(x+3)*(x-1) = 0

x^2-x = 0

x^2-x = 0

x*(x-1) = 0

x-1 = 0 // + 1

x = 1

x*(x-1) = 0

1/(x*(x+3))-3/((x+3)*(x-1))-1/(x*(x-1)) = 0

1/(x*(x+3))+(-3*x)/(x*(x+3))+(-1*(x+3))/(x*(x+3)) = 0

1-1*(x+3)-3*x = 0

1-3*x-x-3 = 0

-4*x-2 = 0

(-4*x-2)/(x*(x+3)) = 0

(-4*x-2)/(x*(x+3)) = 0 // * x*(x+3)

-4*x-2 = 0

-4*x-2 = 0 // + 2

-4*x = 2 // : -4

x = 2/(-4)

x = -1/2

x = -1/2

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