1/(x2-2x-3)

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Solution for 1/(x2-2x-3) equation:


D( x )

x^2-(2*x)-3 = 0

x^2-(2*x)-3 = 0

x^2-(2*x)-3 = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(1*2) or x = (2-16^(1/2))/(1*2)

x = 3 or x = -1

x in (-oo:-1) U (-1:3) U (3:+oo)

1/(x^2-(2*x)-3) = 0

1/(x^2-2*x-3) = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(1*2) or x = (2-16^(1/2))/(1*2)

x = 3 or x = -1

(x+1)*(x-3) = 0

1/((x+1)*(x-3)) = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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