1/(y-1)+2/y+1=3/y

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Solution for 1/(y-1)+2/y+1=3/y equation: 



1/(y-1)+2/y+1=3/y

We move all terms to the left:

1/(y-1)+2/y+1-(3/y)=0



Domain of the equation: (y-1)!=0

We move all terms containing y to the left, all other terms to the right

y!=1

y∈R





Domain of the equation: y!=0

y∈R





Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

1/(y-1)+2/y-(+3/y)+1=0

We get rid of parentheses

1/(y-1)+2/y-3/y+1=0

We calculate fractions


y/(y^2-1y)+(-3y+5)/(y^2-1y)+1=0

We multiply all the terms by the denominator


y+(-3y+5)+1*(y^2-1y)=0

We get rid of parentheses

y-3y+1*(y^2-1y)+5=0

We add all the numbers together, and all the variables

-2y+1*(y^2-1y)+5=0

We move all terms containing y to the left, all other terms to the right

-2y+1*(y^2-1y)=-5

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