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1/(y-2)(y-3)=-2+1/y-3
We move all terms to the left:
1/(y-2)(y-3)-(-2+1/y-3)=0
Domain of the equation: (y-2)(y-3)!=0
We move all terms containing y to the left, all other terms to the right
y-2)(y!=3
y∈R
Domain of the equation: y-3)!=0We add all the numbers together, and all the variables
y∈R
1/(y-2)(y-3)-(1/y-5)=0
We get rid of parentheses
1/(y-2)(y-3)-1/y+5=0
We multiply parentheses ..
1/(+y^2-3y-2y+6)-1/y+5=0
We calculate fractions
We do not support eypression: y^3
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