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1/0.5x+2/x=3
We move all terms to the left:
1/0.5x+2/x-(3)=0
Domain of the equation: 0.5x!=0
x!=0/0.5
x!=0
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
x/(0.5x*x)+x/(0.5x*x)-3=0
We add all the numbers together, and all the variables
x/(+0.5x*x)+x/(+0.5x*x)-3=0
We multiply all the terms by the denominator
x+x-3*(+0.5x*x)=0
We add all the numbers together, and all the variables
2x-3*(+0.5x*x)=0
We multiply parentheses
-0x^2+2x=0
We add all the numbers together, and all the variables
-1x^2+2x=0
a = -1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-1}=\frac{-4}{-2} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-1}=\frac{0}{-2} =0 $
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