1/10(10x-13)=1/5(-5x+14)

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Solution for 1/10(10x-13)=1/5(-5x+14) equation: 



1/10(10x-13)=1/5(-5x+14)

We move all terms to the left:

1/10(10x-13)-(1/5(-5x+14))=0



Domain of the equation: 10(10x-13)!=0

x∈R





Domain of the equation: 5(-5x+14))!=0

x∈R



We calculate fractions


(5x(-)/(10(10x-13)*5(-5x+14)))+(-10x1/(10(10x-13)*5(-5x+14)))=0



We calculate terms in parentheses: +(5x(-)/(10(10x-13)*5(-5x+14))), so:

5x(-)/(10(10x-13)*5(-5x+14))

We add all the numbers together, and all the variables

5x0/(10(10x-13)*5(-5x+14))

We multiply all the terms by the denominator


5x0

We add all the numbers together, and all the variables

5x

Back to the equation:

+(5x)





We calculate terms in parentheses: +(-10x1/(10(10x-13)*5(-5x+14))), so:

-10x1/(10(10x-13)*5(-5x+14))

We multiply all the terms by the denominator


-10x1

We add all the numbers together, and all the variables

-10x

Back to the equation:

+(-10x)



We get rid of parentheses

5x-10x=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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