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1/10(10x-13)=1/5(-5x+14)
We move all terms to the left:
1/10(10x-13)-(1/5(-5x+14))=0
Domain of the equation: 10(10x-13)!=0
x∈R
Domain of the equation: 5(-5x+14))!=0We calculate fractions
x∈R
(5x(-)/(10(10x-13)*5(-5x+14)))+(-10x1/(10(10x-13)*5(-5x+14)))=0
We calculate terms in parentheses: +(5x(-)/(10(10x-13)*5(-5x+14))), so:
5x(-)/(10(10x-13)*5(-5x+14))
We add all the numbers together, and all the variables
5x0/(10(10x-13)*5(-5x+14))
We multiply all the terms by the denominator
5x0
We add all the numbers together, and all the variables
5x
Back to the equation:
+(5x)
We calculate terms in parentheses: +(-10x1/(10(10x-13)*5(-5x+14))), so:We get rid of parentheses
-10x1/(10(10x-13)*5(-5x+14))
We multiply all the terms by the denominator
-10x1
We add all the numbers together, and all the variables
-10x
Back to the equation:
+(-10x)
5x-10x=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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