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1/10(3x-8)=1/5(x+3)
We move all terms to the left:
1/10(3x-8)-(1/5(x+3))=0
Domain of the equation: 10(3x-8)!=0
x∈R
Domain of the equation: 5(x+3))!=0We calculate fractions
x∈R
(5xx/(10(3x-8)*5(x+3)))+(-10x3/(10(3x-8)*5(x+3)))=0
We calculate terms in parentheses: +(5xx/(10(3x-8)*5(x+3))), so:
5xx/(10(3x-8)*5(x+3))
We multiply all the terms by the denominator
5xx
Back to the equation:
+(5xx)
We calculate terms in parentheses: +(-10x3/(10(3x-8)*5(x+3))), so:
-10x3/(10(3x-8)*5(x+3))
We multiply all the terms by the denominator
-10x3
We add all the numbers together, and all the variables
-10x^3
We do not support expression: x^3
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