1/10(3x-8)=1/5(x+3)

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Solution for 1/10(3x-8)=1/5(x+3) equation: 



1/10(3x-8)=1/5(x+3)

We move all terms to the left:

1/10(3x-8)-(1/5(x+3))=0



Domain of the equation: 10(3x-8)!=0

x∈R





Domain of the equation: 5(x+3))!=0

x∈R



We calculate fractions


(5xx/(10(3x-8)*5(x+3)))+(-10x3/(10(3x-8)*5(x+3)))=0



We calculate terms in parentheses: +(5xx/(10(3x-8)*5(x+3))), so:

5xx/(10(3x-8)*5(x+3))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-10x3/(10(3x-8)*5(x+3))), so:

-10x3/(10(3x-8)*5(x+3))

We multiply all the terms by the denominator


-10x3

We add all the numbers together, and all the variables

-10x^3

We do not support expression: x^3

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