1/10(x+54)=-2(3-x

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Solution for 1/10(x+54)=-2(3-x equation: 



1/10(x+54)=-2(3-x

We move all terms to the left:

1/10(x+54)-(-2(3-x)=0



Domain of the equation: 10(x+54)!=0

x∈R



We add all the numbers together, and all the variables

1/10(x+54)-(-2(-1x+3)=0

We multiply all the terms by the denominator


-((-2(-1x+3))*10(x+54)+1=0

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