If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2*cos(x)
ln(x)/x
3*x*(x-5)^2
((5/9)*x^31)/90 = 0
x^2-x^2+2*x^2 = 0
| 3x-4+9x=10 | | 2x+y^2=36 | | (x+9)+(4x^2)=0 | | 5x+1=8x-32 | | 5/9x31/90 | | (f+g)(x)=(x+9)+(4x^2) | | 20+5x=10-8x | | 11.5=14t+20.6 | | 21x+3y=210 | | x^2=-192 | | 30x^3+26x^2+4x= | | x-1/3=12 | | 6x+3x=3x-x | | x/2-3-x≥1 | | 4/(-2-8i) | | 9a+10=64 | | 3x+4.8=12 | | 4(x-7)=6(x-9)+60 | | 1x+2y=60 | | N/24=4/9 | | 0.7xX=29820 | | 8-0.03w=1.8 | | 3(x+4)=x-3 | | 3v+13=40 | | M^2=-49 | | 20+-3(2x+-7)=5(x+5)+-6 | | 9x+4=4x+9 | | 5/18=6/x | | (3x^2+4x-3)=(4x^2-3x+2) | | 10-3(2x-7)=5(x+5)-6 | | -7(x+1)=13 | | y-4=4*(1+0) |