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1/10n+5=3/5n
We move all terms to the left:
1/10n+5-(3/5n)=0
Domain of the equation: 10n!=0
n!=0/10
n!=0
n∈R
Domain of the equation: 5n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
1/10n-(+3/5n)+5=0
We get rid of parentheses
1/10n-3/5n+5=0
We calculate fractions
5n/50n^2+(-30n)/50n^2+5=0
We multiply all the terms by the denominator
5n+(-30n)+5*50n^2=0
Wy multiply elements
250n^2+5n+(-30n)=0
We get rid of parentheses
250n^2+5n-30n=0
We add all the numbers together, and all the variables
250n^2-25n=0
a = 250; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·250·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*250}=\frac{0}{500} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*250}=\frac{50}{500} =1/10 $
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