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1/10x+14.9=-2(3-x)
We move all terms to the left:
1/10x+14.9-(-2(3-x))=0
Domain of the equation: 10x!=0We add all the numbers together, and all the variables
x!=0/10
x!=0
x∈R
1/10x-(-2(-1x+3))+14.9=0
We multiply all the terms by the denominator
-((-2(-1x+3)))*10x+(14.9)*10x+1=0
We multiply parentheses
-((-2(-1x+3)))*10x+149x+1=0
We add all the numbers together, and all the variables
149x-((-2(-1x+3)))*10x+1=0
We move all terms containing x to the left, all other terms to the right
149x-((-2(-1x+3)))*10x=-1
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