1/10x+480=1/2x

Solution for 1/10x+480=1/2x equation:

1/10x+480=1/2x

We move all terms to the left:

1/10x+480-(1/2x)=0


Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/10x-(+1/2x)+480=0

We get rid of parentheses

1/10x-1/2x+480=0

We calculate fractions


2x/20x^2+(-10x)/20x^2+480=0

We multiply all the terms by the denominator


2x+(-10x)+480*20x^2=0

Wy multiply elements

9600x^2+2x+(-10x)=0

We get rid of parentheses

9600x^2+2x-10x=0

We add all the numbers together, and all the variables

9600x^2-8x=0

a = 9600; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·9600·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*9600}=\frac{0}{19200}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*9600}=\frac{16}{19200}
=1/1200
$