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1/10x=6-3/5x
We move all terms to the left:
1/10x-(6-3/5x)=0
Domain of the equation: 10x!=0
x!=0/10
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/10x-(-3/5x+6)=0
We get rid of parentheses
1/10x+3/5x-6=0
We calculate fractions
5x/50x^2+30x/50x^2-6=0
We multiply all the terms by the denominator
5x+30x-6*50x^2=0
We add all the numbers together, and all the variables
35x-6*50x^2=0
Wy multiply elements
-300x^2+35x=0
a = -300; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·(-300)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*-300}=\frac{-70}{-600} =7/60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*-300}=\frac{0}{-600} =0 $
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