1/10y+3=3/5y-2

Solution for 1/10y+3=3/5y-2 equation:

1/10y+3=3/5y-2

We move all terms to the left:

1/10y+3-(3/5y-2)=0


Domain of the equation: 10y!=0

y!=0/10

y!=0

y∈R



Domain of the equation: 5y-2)!=0

y∈R


We get rid of parentheses

1/10y-3/5y+2+3=0

We calculate fractions


5y/50y^2+(-30y)/50y^2+2+3=0

We add all the numbers together, and all the variables

5y/50y^2+(-30y)/50y^2+5=0

We multiply all the terms by the denominator


5y+(-30y)+5*50y^2=0

Wy multiply elements

250y^2+5y+(-30y)=0

We get rid of parentheses

250y^2+5y-30y=0

We add all the numbers together, and all the variables

250y^2-25y=0

a = 250; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·250·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*250}=\frac{0}{500}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*250}=\frac{50}{500}
=1/10
$