1/12(48+24b)=2917-4b)

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Solution for 1/12(48+24b)=2917-4b) equation: 



1/12(48+24b)=2917-4b)

We move all terms to the left:

1/12(48+24b)-(2917-4b))=0



Domain of the equation: 12(48+24b)!=0

b∈R



We add all the numbers together, and all the variables

1/12(24b+48)-(-4b+2917))=0

We get rid of parentheses

1/12(24b+48)+4b-2917)=0

We multiply all the terms by the denominator


4b*12(24b+48)-2917)*12(24b+1+48)=0

We add all the numbers together, and all the variables

4b*12(24b+48)-2917)*12(24b+49)=0

We add all the numbers together, and all the variables

4b*12(24b+48)-2917)*12(24b=0

Wy multiply elements

48b^2(2-2917)*12(24b=0

We add all the numbers together, and all the variables

48b^2(-2915)*12(24b=0

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