1/12(4c+33)=1/4(2c+9)

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Solution for 1/12(4c+33)=1/4(2c+9) equation:



1/12(4c+33)=1/4(2c+9)
We move all terms to the left:
1/12(4c+33)-(1/4(2c+9))=0
Domain of the equation: 12(4c+33)!=0
c∈R
Domain of the equation: 4(2c+9))!=0
c∈R
We calculate fractions
(4c2/(12(4c+33)*4(2c+9)))+(-12c4/(12(4c+33)*4(2c+9)))=0
We calculate terms in parentheses: +(4c2/(12(4c+33)*4(2c+9))), so:
4c2/(12(4c+33)*4(2c+9))
We multiply all the terms by the denominator
4c2
We add all the numbers together, and all the variables
4c^2
Back to the equation:
+(4c^2)
We calculate terms in parentheses: +(-12c4/(12(4c+33)*4(2c+9))), so:
-12c4/(12(4c+33)*4(2c+9))
We multiply all the terms by the denominator
-12c4
We add all the numbers together, and all the variables
-12c^4
We do not support ecpression: c^4

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