1/12(4p+3)=1/4(2p+3)

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Solution for 1/12(4p+3)=1/4(2p+3) equation: 



1/12(4p+3)=1/4(2p+3)

We move all terms to the left:

1/12(4p+3)-(1/4(2p+3))=0



Domain of the equation: 12(4p+3)!=0

p∈R





Domain of the equation: 4(2p+3))!=0

p∈R



We calculate fractions


(4p2/(12(4p+3)*4(2p+3)))+(-12p4/(12(4p+3)*4(2p+3)))=0



We calculate terms in parentheses: +(4p2/(12(4p+3)*4(2p+3))), so:

4p2/(12(4p+3)*4(2p+3))

We multiply all the terms by the denominator


4p2

We add all the numbers together, and all the variables

4p^2

Back to the equation:

+(4p^2)





We calculate terms in parentheses: +(-12p4/(12(4p+3)*4(2p+3))), so:

-12p4/(12(4p+3)*4(2p+3))

We multiply all the terms by the denominator


-12p4

We add all the numbers together, and all the variables

-12p^4

We do not support eppression: p^4

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