1/12(4x+39)=1/4(2x+9)

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Solution for 1/12(4x+39)=1/4(2x+9) equation: 



1/12(4x+39)=1/4(2x+9)

We move all terms to the left:

1/12(4x+39)-(1/4(2x+9))=0



Domain of the equation: 12(4x+39)!=0

x∈R





Domain of the equation: 4(2x+9))!=0

x∈R



We calculate fractions


(4x2/(12(4x+39)*4(2x+9)))+(-12x4/(12(4x+39)*4(2x+9)))=0



We calculate terms in parentheses: +(4x2/(12(4x+39)*4(2x+9))), so:

4x2/(12(4x+39)*4(2x+9))

We multiply all the terms by the denominator


4x2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)





We calculate terms in parentheses: +(-12x4/(12(4x+39)*4(2x+9))), so:

-12x4/(12(4x+39)*4(2x+9))

We multiply all the terms by the denominator


-12x4

We add all the numbers together, and all the variables

-12x^4

We do not support expression: x^4

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