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1/12(5x+4)=1/15(7x+2)
We move all terms to the left:
1/12(5x+4)-(1/15(7x+2))=0
Domain of the equation: 12(5x+4)!=0
x∈R
Domain of the equation: 15(7x+2))!=0We calculate fractions
x∈R
(15x7/(12(5x+4)*15(7x+2)))+(-12x5/(12(5x+4)*15(7x+2)))=0
We calculate terms in parentheses: +(15x7/(12(5x+4)*15(7x+2))), so:
15x7/(12(5x+4)*15(7x+2))
We multiply all the terms by the denominator
15x7
We add all the numbers together, and all the variables
15x^7
We do not support expression: x^7
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