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1/12(a-8)=1/3(2a+5)
We move all terms to the left:
1/12(a-8)-(1/3(2a+5))=0
Domain of the equation: 12(a-8)!=0
a∈R
Domain of the equation: 3(2a+5))!=0We calculate fractions
a∈R
(3a2/(12(a-8)*3(2a+5)))+(-12aa/(12(a-8)*3(2a+5)))=0
We calculate terms in parentheses: +(3a2/(12(a-8)*3(2a+5))), so:
3a2/(12(a-8)*3(2a+5))
We multiply all the terms by the denominator
3a2
We add all the numbers together, and all the variables
3a^2
Back to the equation:
+(3a^2)
We calculate terms in parentheses: +(-12aa/(12(a-8)*3(2a+5))), so:We get rid of parentheses
-12aa/(12(a-8)*3(2a+5))
We multiply all the terms by the denominator
-12aa
Back to the equation:
+(-12aa)
3a^2-12aa=0
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