1/12(a-8)=1/3(2a+5)

Solution for 1/12(a-8)=1/3(2a+5) equation:

1/12(a-8)=1/3(2a+5)

We move all terms to the left:

1/12(a-8)-(1/3(2a+5))=0


Domain of the equation: 12(a-8)!=0

a∈R



Domain of the equation: 3(2a+5))!=0

a∈R


We calculate fractions


(3a2/(12(a-8)*3(2a+5)))+(-12aa/(12(a-8)*3(2a+5)))=0


We calculate terms in parentheses: +(3a2/(12(a-8)*3(2a+5))), so:

3a2/(12(a-8)*3(2a+5))

We multiply all the terms by the denominator


3a2

We add all the numbers together, and all the variables

3a^2

Back to the equation:

+(3a^2)



We calculate terms in parentheses: +(-12aa/(12(a-8)*3(2a+5))), so:

-12aa/(12(a-8)*3(2a+5))

We multiply all the terms by the denominator


-12aa

Back to the equation:

+(-12aa)


We get rid of parentheses

3a^2-12aa=0