1/12(x-4y-3z)

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Solution for 1/12(x-4y-3z) equation: 


x in (-oo:+oo)

(1/12)*(x-(4*y)-(3*z)) = 0

(1/12)*(x-4*y-3*z) = 0

1/12*(x-4*y-3*z) = 0

( 1/12 )

1/12 = 0

x belongs to the empty set

( x-4*y-3*z )

x-4*y-3*z = 0 // + -4*y-3*z

x = -(-4*y-3*z)

x = -(-4*y-3*z)

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