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1/12(x-54)=1+x
We move all terms to the left:
1/12(x-54)-(1+x)=0
Domain of the equation: 12(x-54)!=0We add all the numbers together, and all the variables
x∈R
1/12(x-54)-(x+1)=0
We get rid of parentheses
1/12(x-54)-x-1=0
We multiply all the terms by the denominator
-x*12(x-54)-1*12(x-54)+1=0
Wy multiply elements
-12x^2(x-12x(x+1=0
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