1/12(x-86)=2+x

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Solution for 1/12(x-86)=2+x equation: 



1/12(x-86)=2+x

We move all terms to the left:

1/12(x-86)-(2+x)=0



Domain of the equation: 12(x-86)!=0

x∈R



We add all the numbers together, and all the variables

1/12(x-86)-(x+2)=0

We get rid of parentheses

1/12(x-86)-x-2=0

We multiply all the terms by the denominator


-x*12(x-86)-2*12(x-86)+1=0

Wy multiply elements

-12x^2(x-24x(x+1=0

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