1/12b+4=1/8b+88

Solution for 1/12b+4=1/8b+88 equation:

1/12b+4=1/8b+88

We move all terms to the left:

1/12b+4-(1/8b+88)=0


Domain of the equation: 12b!=0

b!=0/12

b!=0

b∈R



Domain of the equation: 8b+88)!=0

b∈R


We get rid of parentheses

1/12b-1/8b-88+4=0

We calculate fractions


8b/96b^2+(-12b)/96b^2-88+4=0

We add all the numbers together, and all the variables

8b/96b^2+(-12b)/96b^2-84=0

We multiply all the terms by the denominator


8b+(-12b)-84*96b^2=0

Wy multiply elements

-8064b^2+8b+(-12b)=0

We get rid of parentheses

-8064b^2+8b-12b=0

We add all the numbers together, and all the variables

-8064b^2-4b=0

a = -8064; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-8064)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-8064}=\frac{0}{-16128}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-8064}=\frac{8}{-16128}
=-1/2016
$