1/12m+2/3m=60

Solution for 1/12m+2/3m=60 equation:

1/12m+2/3m=60

We move all terms to the left:

1/12m+2/3m-(60)=0


Domain of the equation: 12m!=0

m!=0/12

m!=0

m∈R



Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R


We calculate fractions


3m/36m^2+24m/36m^2-60=0

We multiply all the terms by the denominator


3m+24m-60*36m^2=0

We add all the numbers together, and all the variables

27m-60*36m^2=0

Wy multiply elements

-2160m^2+27m=0

a = -2160; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-2160)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-2160}=\frac{-54}{-4320}
=1/80
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-2160}=\frac{0}{-4320}
=0
$