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1/12t=3
We move all terms to the left:
1/12t-(3)=0
Domain of the equation: 12t!=0We multiply all the terms by the denominator
t!=0/12
t!=0
t∈R
-3*12t+1=0
Wy multiply elements
-36t+1=0
We move all terms containing t to the left, all other terms to the right
-36t=-1
t=-1/-36
t=1/36
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