1/12x+1/8x=1

Solution for 1/12x+1/8x=1 equation:

1/12x+1/8x=1

We move all terms to the left:

1/12x+1/8x-(1)=0


Domain of the equation: 12x!=0

x!=0/12

x!=0

x∈R



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We calculate fractions


8x/96x^2+12x/96x^2-1=0

We multiply all the terms by the denominator


8x+12x-1*96x^2=0

We add all the numbers together, and all the variables

20x-1*96x^2=0

Wy multiply elements

-96x^2+20x=0

a = -96; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-96)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-96}=\frac{-40}{-192}
=5/24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-96}=\frac{0}{-192}
=0
$