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1/12x-2=1/2x-12
We move all terms to the left:
1/12x-2-(1/2x-12)=0
Domain of the equation: 12x!=0
x!=0/12
x!=0
x∈R
Domain of the equation: 2x-12)!=0We get rid of parentheses
x∈R
1/12x-1/2x+12-2=0
We calculate fractions
2x/24x^2+(-12x)/24x^2+12-2=0
We add all the numbers together, and all the variables
2x/24x^2+(-12x)/24x^2+10=0
We multiply all the terms by the denominator
2x+(-12x)+10*24x^2=0
Wy multiply elements
240x^2+2x+(-12x)=0
We get rid of parentheses
240x^2+2x-12x=0
We add all the numbers together, and all the variables
240x^2-10x=0
a = 240; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·240·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*240}=\frac{0}{480} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*240}=\frac{20}{480} =1/24 $
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