1/15(x+5)=1/9(4-x)

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Solution for 1/15(x+5)=1/9(4-x) equation: 



1/15(x+5)=1/9(4-x)

We move all terms to the left:

1/15(x+5)-(1/9(4-x))=0



Domain of the equation: 15(x+5)!=0

x∈R





Domain of the equation: 9(4-x))!=0

x∈R



We add all the numbers together, and all the variables

1/15(x+5)-(1/9(-1x+4))=0

We calculate fractions


(9x(-)/(15(x+5)*9(-1x+4)))+(-15xx/(15(x+5)*9(-1x+4)))=0



We calculate terms in parentheses: +(9x(-)/(15(x+5)*9(-1x+4))), so:

9x(-)/(15(x+5)*9(-1x+4))

We add all the numbers together, and all the variables

9x0/(15(x+5)*9(-1x+4))

We multiply all the terms by the denominator


9x0

We add all the numbers together, and all the variables

9x

Back to the equation:

+(9x)





We calculate terms in parentheses: +(-15xx/(15(x+5)*9(-1x+4))), so:

-15xx/(15(x+5)*9(-1x+4))

We multiply all the terms by the denominator


-15xx

Back to the equation:

+(-15xx)



We get rid of parentheses

9x-15xx=0

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