1/16(x+2)(x-4)(x-6)=0

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Solution for 1/16(x+2)(x-4)(x-6)=0 equation: 


x in (-oo:+oo)

(1/16)*(x+2)*(x-4)*(x-6) = 0

1/16*(x+2)*(x-4)*(x-6) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-4 )

x-4 = 0 // + 4

x = 4

( x-6 )

x-6 = 0 // + 6

x = 6

x in { -2, 4, 6 }

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