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D( x )
x <= 0
x <= 0
x in (0:+oo)
(1/19)*(ln(x)-(5*ln(y))) = 0
(1/19)*(ln(x)-5*ln(y)) = 0
t_1 = ln(x)
t_2 = ln(y)
(1/19)*(t_1-5*ln(y)) = 0
1/19*(t_1-5*t_2) = 0
t_1-5*t_2 = 0
1/19*(t_1-5*t_2) = 0
t_1-5*t_2 = 0 // + -5*t_2
t_1 = -(-5*t_2)
t_1 = 5*t_2
t_1 = 5*ln(y)
ln(x) = 5*ln(y)
ln(x) = ln(e^(5*ln(y)))
x = e^(5*ln(y))
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