1/19(ln(x)-5ln(y))

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Solution for 1/19(ln(x)-5ln(y)) equation: 


D( x )

x <= 0

x <= 0

x in (0:+oo)

(1/19)*(ln(x)-(5*ln(y))) = 0

(1/19)*(ln(x)-5*ln(y)) = 0

t_1 = ln(x)

t_2 = ln(y)

(1/19)*(t_1-5*ln(y)) = 0

1/19*(t_1-5*t_2) = 0

t_1-5*t_2 = 0

1/19*(t_1-5*t_2) = 0

t_1-5*t_2 = 0 // + -5*t_2

t_1 = -(-5*t_2)

t_1 = 5*t_2

t_1 = 5*ln(y)

ln(x) = 5*ln(y)

ln(x) = ln(e^(5*ln(y)))

x = e^(5*ln(y))

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