1/2(-12x-10)=1/2(-2x-50)

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Solution for 1/2(-12x-10)=1/2(-2x-50) equation: 



1/2(-12x-10)=1/2(-2x-50)

We move all terms to the left:

1/2(-12x-10)-(1/2(-2x-50))=0



Domain of the equation: 2(-12x-10)!=0

x∈R





Domain of the equation: 2(-2x-50))!=0

x∈R



We calculate fractions


(2x(-)/(2(-12x-10)*2(-2x-50)))+(-2x0/(2(-12x-10)*2(-2x-50)))=0



We calculate terms in parentheses: +(2x(-)/(2(-12x-10)*2(-2x-50))), so:

2x(-)/(2(-12x-10)*2(-2x-50))

We add all the numbers together, and all the variables

2x0/(2(-12x-10)*2(-2x-50))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-2x0/(2(-12x-10)*2(-2x-50))), so:

-2x0/(2(-12x-10)*2(-2x-50))

We multiply all the terms by the denominator


-2x0

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

2x-2x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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