1/2(-2x+10)+9=10(x+1)+5

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Solution for 1/2(-2x+10)+9=10(x+1)+5 equation:



1/2(-2x+10)+9=10(x+1)+5
We move all terms to the left:
1/2(-2x+10)+9-(10(x+1)+5)=0
Domain of the equation: 2(-2x+10)!=0
x∈R
We multiply all the terms by the denominator
-((10(x+1)+5))*2(-2x+10)+9*2(-2x+10)+1=0
We calculate terms in parentheses: -((10(x+1)+5))*2(-2x+10), so:
(10(x+1)+5))*2(-2x+10
We add all the numbers together, and all the variables
-2x+(10(x+1)+5))*2(+10
Back to the equation:
-(-2x+(10(x+1)+5))*2(+10)
We add all the numbers together, and all the variables
-(-2x+(10(x+1)+5))*210+9*2(-2x+10)+1=0
Wy multiply elements
-(-2x+(10(x+1)+5))*210+18x(-+1=0
We use the square of the difference formula
-(-2x+(10(x+1)+5))*210+18x(-1=0

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