1/2(-4x+2)-6=10x-8

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Solution for 1/2(-4x+2)-6=10x-8 equation: 



1/2(-4x+2)-6=10x-8

We move all terms to the left:

1/2(-4x+2)-6-(10x-8)=0



Domain of the equation: 2(-4x+2)!=0

x∈R



We get rid of parentheses

1/2(-4x+2)-10x+8-6=0

We multiply all the terms by the denominator


-10x*2(-4x+2)+8*2(-4x+2)-6*2(-4x+2)+1=0

Wy multiply elements

-20x^2(-+16x(--12x(-+1=0

We use the square of the difference formula

-20x^2(-16x(+12x(-1=0

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