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1/2(-4x+4)=2/3(9-3x)
We move all terms to the left:
1/2(-4x+4)-(2/3(9-3x))=0
Domain of the equation: 2(-4x+4)!=0
x∈R
Domain of the equation: 3(9-3x))!=0We add all the numbers together, and all the variables
x∈R
1/2(-4x+4)-(2/3(-3x+9))=0
We calculate fractions
(3x(-)/(2(-4x+4)*3(-3x+9)))+(-4x0/(2(-4x+4)*3(-3x+9)))=0
We calculate terms in parentheses: +(3x(-)/(2(-4x+4)*3(-3x+9))), so:
3x(-)/(2(-4x+4)*3(-3x+9))
We add all the numbers together, and all the variables
3x0/(2(-4x+4)*3(-3x+9))
We multiply all the terms by the denominator
3x0
We add all the numbers together, and all the variables
3x
Back to the equation:
+(3x)
We calculate terms in parentheses: +(-4x0/(2(-4x+4)*3(-3x+9))), so:We get rid of parentheses
-4x0/(2(-4x+4)*3(-3x+9))
We multiply all the terms by the denominator
-4x0
We add all the numbers together, and all the variables
-4x
Back to the equation:
+(-4x)
3x-4x=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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