1/2(1+1/3y)+2/3y=-19/2

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Solution for 1/2(1+1/3y)+2/3y=-19/2 equation: 


y in (-oo:+oo)

(1/2)*((1/3)*y+1)+(2/3)*y = -19/2 // + -19/2

(1/2)*((1/3)*y+1)+(2/3)*y-(-19/2) = 0

(1/2)*((1/3)*y+1)+(2/3)*y+19/2 = 0

1/2*(1/3*y+1)+(2*y)/3+19/2 = 0

(1/2*2*3*(1/3*y+1))/(2*3)+(2*2*y)/(2*3)+(3*19)/(2*3) = 0

1/2*2*3*(1/3*y+1)+2*2*y+3*19 = 0

5*y+3+57 = 0

5*y+60 = 0

(5*y+60)/(2*3) = 0

(5*y+60)/(2*3) = 0 // * 2*3

5*y+60 = 0

5*y+60 = 0 // - 60

5*y = -60 // : 5

y = -60/5

y = -12

y = -12

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