1/2(1-c)=11/6c

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Solution for 1/2(1-c)=11/6c equation: 



1/2(1-c)=11/6c

We move all terms to the left:

1/2(1-c)-(11/6c)=0



Domain of the equation: 2(1-c)!=0

c∈R





Domain of the equation: 6c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

1/2(-1c+1)-(+11/6c)=0

We get rid of parentheses

1/2(-1c+1)-11/6c=0

We calculate fractions


6c/(-12c^2+12c)+(-22c(-)/(-12c^2+12c)=0



We calculate terms in parentheses: +(-22c(-)/(-12c^2+12c), so:

-22c(-)/(-12c^2+12c

We add all the numbers together, and all the variables

-22c0/(-12c^2+12c

We multiply all the terms by the denominator


-22c0

We add all the numbers together, and all the variables

-22c

Back to the equation:

+(-22c)



We get rid of parentheses

6c/(-12c^2+12c)-22c=0

We multiply all the terms by the denominator


-22c*(-12c^2+12c)+6c=0

We multiply parentheses

264c^3-264c^2+6c=0

We do not support ecpression: c^3

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