1/2(1-x)=1/3(x-4)

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Solution for 1/2(1-x)=1/3(x-4) equation: 



1/2(1-x)=1/3(x-4)

We move all terms to the left:

1/2(1-x)-(1/3(x-4))=0



Domain of the equation: 2(1-x)!=0

x∈R





Domain of the equation: 3(x-4))!=0

x∈R



We add all the numbers together, and all the variables

1/2(-1x+1)-(1/3(x-4))=0

We calculate fractions


(3xx/(2(-1x+1)*3(x-4)))+(-2x0/(2(-1x+1)*3(x-4)))=0



We calculate terms in parentheses: +(3xx/(2(-1x+1)*3(x-4))), so:

3xx/(2(-1x+1)*3(x-4))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-2x0/(2(-1x+1)*3(x-4))), so:

-2x0/(2(-1x+1)*3(x-4))

We multiply all the terms by the denominator


-2x0

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

3xx-2x=0

We add all the numbers together, and all the variables

-2x+3xx=0

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