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1/2(10-2p)=3(2p-3)
We move all terms to the left:
1/2(10-2p)-(3(2p-3))=0
Domain of the equation: 2(10-2p)!=0We add all the numbers together, and all the variables
p∈R
1/2(-2p+10)-(3(2p-3))=0
We multiply all the terms by the denominator
-((3(2p-3)))*2(-2p+10)+1=0
We calculate terms in parentheses: -((3(2p-3)))*2(-2p+10), so:We add all the numbers together, and all the variables
(3(2p-3)))*2(-2p+10
We add all the numbers together, and all the variables
-2p+(3(2p-3)))*2(+10
Back to the equation:
-(-2p+(3(2p-3)))*2(+10)
-(-2p+(3(2p-3)))*210+1=0
We move all terms containing p to the left, all other terms to the right
-(-2p+(3(2p-3)))*210=-1
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