1/2(10-2x)-6=5x+2(x-6)

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Solution for 1/2(10-2x)-6=5x+2(x-6) equation: 



1/2(10-2x)-6=5x+2(x-6)

We move all terms to the left:

1/2(10-2x)-6-(5x+2(x-6))=0



Domain of the equation: 2(10-2x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-2x+10)-(5x+2(x-6))-6=0

We multiply all the terms by the denominator


-((5x+2(x-6)))*2(-2x+10)-6*2(-2x+10)+1=0



We calculate terms in parentheses: -((5x+2(x-6)))*2(-2x+10), so:

(5x+2(x-6)))*2(-2x+10

We add all the numbers together, and all the variables

-2x+(5x+2(x-6)))*2(+10

Back to the equation:

-(-2x+(5x+2(x-6)))*2(+10)



We add all the numbers together, and all the variables

-(-2x+(5x+2(x-6)))*210-6*2(-2x+10)+1=0

Wy multiply elements

-(-2x+(5x+2(x-6)))*210-12x(-+1=0

We use the square of the difference formula

-(-2x+(5x+2(x-6)))*210-12x(-1=0

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