1/2(10-2x)=3(2x-3)

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Solution for 1/2(10-2x)=3(2x-3) equation: 



1/2(10-2x)=3(2x-3)

We move all terms to the left:

1/2(10-2x)-(3(2x-3))=0



Domain of the equation: 2(10-2x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-2x+10)-(3(2x-3))=0

We multiply all the terms by the denominator


-((3(2x-3)))*2(-2x+10)+1=0



We calculate terms in parentheses: -((3(2x-3)))*2(-2x+10), so:

(3(2x-3)))*2(-2x+10

We add all the numbers together, and all the variables

-2x+(3(2x-3)))*2(+10

Back to the equation:

-(-2x+(3(2x-3)))*2(+10)



We add all the numbers together, and all the variables

-(-2x+(3(2x-3)))*210+1=0

We move all terms containing x to the left, all other terms to the right

-(-2x+(3(2x-3)))*210=-1

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