1/2(10-8x)+6x=19

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Solution for 1/2(10-8x)+6x=19 equation: 



1/2(10-8x)+6x=19

We move all terms to the left:

1/2(10-8x)+6x-(19)=0



Domain of the equation: 2(10-8x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-8x+10)+6x-19=0

We add all the numbers together, and all the variables

6x+1/2(-8x+10)-19=0

We multiply all the terms by the denominator


6x*2(-8x+10)-19*2(-8x+10)+1=0

Wy multiply elements

12x^2(--38x(-+1=0

We use the square of the difference formula

12x^2(+38x(-1=0

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