1/2(10b)=35

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Solution for 1/2(10b)=35 equation: 



1/2(10b)=35

We move all terms to the left:

1/2(10b)-(35)=0



Domain of the equation: 210b!=0

b!=0/210

b!=0

b∈R



We multiply all the terms by the denominator


-35*210b+1=0

Wy multiply elements

-7350b+1=0

We move all terms containing b to the left, all other terms to the right

-7350b=-1

b=-1/-7350

b=1/7350

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