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1/2(10x+10)-17=-1/5(35x-15)
We move all terms to the left:
1/2(10x+10)-17-(-1/5(35x-15))=0
Domain of the equation: 2(10x+10)!=0
x∈R
Domain of the equation: 5(35x-15))!=0We calculate fractions
x∈R
(5x3/(2(10x+10)*5(35x-15)))+(-(-2x1)/(2(10x+10)*5(35x-15)))-17=0
We calculate terms in parentheses: +(5x3/(2(10x+10)*5(35x-15))), so:
5x3/(2(10x+10)*5(35x-15))
We multiply all the terms by the denominator
5x3
We add all the numbers together, and all the variables
5x^3
We do not support expression: x^3
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