1/2(10x+12)-8=-1/5(15x-10)

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Solution for 1/2(10x+12)-8=-1/5(15x-10) equation: 



1/2(10x+12)-8=-1/5(15x-10)

We move all terms to the left:

1/2(10x+12)-8-(-1/5(15x-10))=0



Domain of the equation: 2(10x+12)!=0

x∈R





Domain of the equation: 5(15x-10))!=0

x∈R



We calculate fractions


(5x1/(2(10x+12)*5(15x-10)))+(-(-2x1)/(2(10x+12)*5(15x-10)))-8=0



We calculate terms in parentheses: +(5x1/(2(10x+12)*5(15x-10))), so:

5x1/(2(10x+12)*5(15x-10))

We multiply all the terms by the denominator


5x1

We add all the numbers together, and all the variables

5x

Back to the equation:

+(5x)





We calculate terms in parentheses: +(-(-2x1)/(2(10x+12)*5(15x-10))), so:

-(-2x1)/(2(10x+12)*5(15x-10))

We add all the numbers together, and all the variables

-(-2x)/(2(10x+12)*5(15x-10))

We multiply all the terms by the denominator


-(-2x)

We get rid of parentheses

2x

Back to the equation:

+(2x)



We add all the numbers together, and all the variables

7x-8=0

We move all terms containing x to the left, all other terms to the right

7x=8

x=8/7

x=1+1/7

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