1/2(10x+12)=1/3(12x+15)

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Solution for 1/2(10x+12)=1/3(12x+15) equation: 



1/2(10x+12)=1/3(12x+15)

We move all terms to the left:

1/2(10x+12)-(1/3(12x+15))=0



Domain of the equation: 2(10x+12)!=0

x∈R





Domain of the equation: 3(12x+15))!=0

x∈R



We calculate fractions


(3x1/(2(10x+12)*3(12x+15)))+(-2x1/(2(10x+12)*3(12x+15)))=0



We calculate terms in parentheses: +(3x1/(2(10x+12)*3(12x+15))), so:

3x1/(2(10x+12)*3(12x+15))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-2x1/(2(10x+12)*3(12x+15))), so:

-2x1/(2(10x+12)*3(12x+15))

We multiply all the terms by the denominator


-2x1

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

3x-2x=0

We add all the numbers together, and all the variables

x=0

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