1/2(10x+4)+2x=8-(3x-4)

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Solution for 1/2(10x+4)+2x=8-(3x-4) equation: 



1/2(10x+4)+2x=8-(3x-4)

We move all terms to the left:

1/2(10x+4)+2x-(8-(3x-4))=0



Domain of the equation: 2(10x+4)!=0

x∈R



We add all the numbers together, and all the variables

2x+1/2(10x+4)-(8-(3x-4))=0

We multiply all the terms by the denominator


2x*2(10x+4)-((8-(3x-4)))*2(10x+4)+1=0



We calculate terms in parentheses: -((8-(3x-4)))*2(10x+4), so:

(8-(3x-4)))*2(10x+4



Wy multiply elements

4x^2(1-((8-(3x-4)))*2(10x+4)+1=0

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