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1/2(10x+42)=12+5x
We move all terms to the left:
1/2(10x+42)-(12+5x)=0
Domain of the equation: 2(10x+42)!=0We add all the numbers together, and all the variables
x∈R
1/2(10x+42)-(5x+12)=0
We get rid of parentheses
1/2(10x+42)-5x-12=0
We multiply all the terms by the denominator
-5x*2(10x+42)-12*2(10x+42)+1=0
Wy multiply elements
-10x^2(1-24x(1+1=0
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