1/2(10x-20)=1/2(8x+20)

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Solution for 1/2(10x-20)=1/2(8x+20) equation: 



1/2(10x-20)=1/2(8x+20)

We move all terms to the left:

1/2(10x-20)-(1/2(8x+20))=0



Domain of the equation: 2(10x-20)!=0

x∈R





Domain of the equation: 2(8x+20))!=0

x∈R



We calculate fractions


(2x8/(2(10x-20)*2(8x+20)))+(-2x1/(2(10x-20)*2(8x+20)))=0



We calculate terms in parentheses: +(2x8/(2(10x-20)*2(8x+20))), so:

2x8/(2(10x-20)*2(8x+20))

We multiply all the terms by the denominator


2x8

We add all the numbers together, and all the variables

2x^8

We do not support expression: x^8

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