1/2(10x-4)=5x-3+1

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Solution for 1/2(10x-4)=5x-3+1 equation: 



1/2(10x-4)=5x-3+1

We move all terms to the left:

1/2(10x-4)-(5x-3+1)=0



Domain of the equation: 2(10x-4)!=0

x∈R



We add all the numbers together, and all the variables

1/2(10x-4)-(5x-2)=0

We get rid of parentheses

1/2(10x-4)-5x+2=0

We multiply all the terms by the denominator


-5x*2(10x-4)+2*2(10x-4)+1=0

Wy multiply elements

-10x^2(1+4x(1+1=0

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